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Answer by Ran Adler for Initialization of an ArrayList in one line

List<String> names = Arrays.asList("2", "@2234", "21", "11");

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Answer by Mark for Initialization of an ArrayList in one line

Collection literals didn't make it into Java 8, but it is possible to use the Stream API to initialize a list in one rather long line:List<String> places = Stream.of("Buenos Aires", "Córdoba",...

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Answer by user2801794 for Initialization of an ArrayList in one line

Simply use below code as follows.List<String> list = new ArrayList<String>() {{ add("A"); add("B"); add("C");}};

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Answer by Paweł Adamski for Initialization of an ArrayList in one line

With Guava you can write:ArrayList<String> places = Lists.newArrayList("Buenos Aires", "Córdoba", "La Plata");In Guava there are also other useful static constructors. You can read about them here.

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Answer by Ozzy for Initialization of an ArrayList in one line

Like Tom said:List<String> places = Arrays.asList("Buenos Aires", "Córdoba", "La Plata");But since you complained of wanting an ArrayList, you should first know that ArrayList is a subclass of...

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Answer by user439407 for Initialization of an ArrayList in one line

(Should be a comment, but too long, so new reply). As others have mentioned, the Arrays.asList method is fixed size, but that's not the only issue with it. It also doesn't handle inheritance very well....

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Answer by Adrian for Initialization of an ArrayList in one line

Actually, it's possible to do it in one line:Arrays.asList(new MyClass[] {new MyClass("arg1"), new MyClass("arg2")})

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Answer by abaelter for Initialization of an ArrayList in one line

public static <T> List<T> asList(T... a) { return new ArrayList<T>(a);}This is the implementation of Arrays.asList, so you could go withArrayList<String> arr =...

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Answer by Dawg for Initialization of an ArrayList in one line

In Java, you can't doArrayList<String> places = new ArrayList<String>( Arrays.asList("Buenos Aires", "Córdoba", "La Plata"));As was pointed out, you'd need to do a double brace...

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Answer by Randyaa for Initialization of an ArrayList in one line

If you need a simple list of size 1:List<String> strings = new ArrayList<String>(Collections.singletonList("A"));If you need a list of several objects:List<String> strings = new...

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Answer by Christoffer Hammarström for Initialization of an ArrayList in one line

The simple answerJava 9 or later:List<String> strings = List.of("foo", "bar", "baz");List.of(...) will give you an immutableList, so it cannot be changed.Which is what you want in most cases...

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Answer by George for Initialization of an ArrayList in one line

import com.google.common.collect.ImmutableList;....List<String> places = ImmutableList.of("Buenos Aires", "Córdoba", "La Plata");

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Answer by Jordão for Initialization of an ArrayList in one line

You could create a factory method:public static ArrayList<String> createArrayList(String ... elements) { ArrayList<String> list = new ArrayList<String>(); for (String element :...

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Answer by Tom for Initialization of an ArrayList in one line

It would be simpler if you were to just declare it as a List - does it have to be an ArrayList?List<String> places = Arrays.asList("Buenos Aires", "Córdoba", "La Plata");Or if you have only one...

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Answer by coobird for Initialization of an ArrayList in one line

Actually, probably the "best" way to initialize the ArrayList is the method you wrote, as it does not need to create a new List in any way:ArrayList<String> list = new...

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Initialization of an ArrayList in one line

I wanted to create a list of options for testing purposes. At first, I did this:ArrayList<String> places = new ArrayList<String>();places.add("Buenos...

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Answer by Amar kumar Nayak for Initialization of an ArrayList in one line

You can use of() method from java 9 onwardsList<String> places = List.of("Buenos Aires","Córdoba","La Plata");of() methods create immutable list.If you want to modifie you got exception.

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