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Answer by Old Firm for Initialization of an ArrayList in one line
I suspect the original question relates to a desire to declare and initialize the ArrayList in one line and avoid having to create separate code to acheive the initialization. Thus, the answer lies in...
View ArticleAnswer by Ajay Singh for Initialization of an ArrayList in one line
There are multiple ways to create and initialize list in one line. Some examples://Using Double brace initialization, creates a new (anonymous) subclass of ArrayListList<String> list1 = new...
View ArticleAnswer by PRANAV SINGH for Initialization of an ArrayList in one line
Simplest way : you can use this approach to add multiple elements to any type of collection like ArrayList and HashSetArrayList<String> allViews = new...
View ArticleAnswer by Akila for Initialization of an ArrayList in one line
Using Arrays.asList("Buenos Aires", "Córdoba", "La Plata"); is correct. but Any calls to Arrays.asList() with zero arguments or only one argument could be replaced with either a call to...
View ArticleAnswer by Kaplan for Initialization of an ArrayList in one line
interestingly no one-liner with the other overloadedStream::collectmethod is listedArrayList<String> places = Stream.of( "Buenos Aires", "Córdoba", "La Plata" ).collect( ArrayList::new,...
View ArticleAnswer by Stefan Reich for Initialization of an ArrayList in one line
Why not make a simple utility function that does this?static <A> ArrayList<A> ll(A... a) { ArrayList l = new ArrayList(a.length); for (A x : a) l.add(x); return l;}"ll" stands for "literal...
View ArticleAnswer by Mohit Tyagi for Initialization of an ArrayList in one line
In Java 9 we can easily initialize an ArrayList in a single line:List<String> places = List.of("Buenos Aires", "Córdoba", "La Plata");orList<String> places = new...
View ArticleAnswer by yegor256 for Initialization of an ArrayList in one line
You can use StickyList from Cactoos:List<String> names = new StickyList<>("Scott Fitzgerald", "Fyodor Dostoyevsky");
View ArticleAnswer by rashedcs for Initialization of an ArrayList in one line
You can use the below statements:Code Snippet:String [] arr = {"Sharlock", "Homes", "Watson"};List<String> names = Arrays.asList(arr);
View ArticleAnswer by Henok T for Initialization of an ArrayList in one line
Here is another way:List<String> values = Stream.of("One", "Two").collect(Collectors.toList());
View ArticleAnswer by Naman for Initialization of an ArrayList in one line
With java-9 and above, as suggested in JEP 269: Convenience Factory Methods for Collections, this could be achieved using collection literals now with -List<String> list = List.of("A", "B",...
View ArticleAnswer by user85421 for Initialization of an ArrayList in one line
Java 9 has the following method to create an immutable list as documented (or documented as unmodifiableJava 10+):List<String> places = List.of("Buenos Aires", "Córdoba", "La Plata");which is...
View ArticleAnswer by user_3380739 for Initialization of an ArrayList in one line
Here is code by abacus-common// ArrayListList<String> list = N.asList("Buenos Aires", "Córdoba", "La Plata");// HashSetSet<String> set = N.asSet("Buenos Aires", "Córdoba", "La Plata");//...
View ArticleAnswer by Akash Manngroliya for Initialization of an ArrayList in one line
Yes with the help of Arrays you can initialize array list in one line,List<String> strlist= Arrays.asList("aaa", "bbb", "ccc");
View ArticleAnswer by Charif DZ for Initialization of an ArrayList in one line
The best way to do it:package main_package;import java.util.ArrayList;public class Stackkkk { public static void main(String[] args) { ArrayList<Object> list = new ArrayList<Object>();...
View ArticleAnswer by Ant20 for Initialization of an ArrayList in one line
Try with this code line:Collections.singletonList(provider)
View ArticleAnswer by ViliusK for Initialization of an ArrayList in one line
Collections.singletonList(messageBody)If you'd need to have a list of one item!Collections is from java.util package.
View ArticleAnswer by Donald Raab for Initialization of an ArrayList in one line
With Eclipse Collections you can write the following:List<String> list = Lists.mutable.with("Buenos Aires", "Córdoba", "La Plata");You can also be more specific about the types and whether they...
View ArticleAnswer by Richard B for Initialization of an ArrayList in one line
About the most compact way to do this is:Double array[] = { 1.0, 2.0, 3.0};List<Double> list = Arrays.asList(array);
View ArticleAnswer by Manoj Kumar for Initialization of an ArrayList in one line
For me, Arrays.asList() is the best and most convenient one. I always like to initialize that way.If you are a beginner in Java Collections then I would like you to refer ArrayList initialization.
View ArticleAnswer by Ran Adler for Initialization of an ArrayList in one line
List<String> names = Arrays.asList("2", "@2234", "21", "11");
View ArticleAnswer by Mark for Initialization of an ArrayList in one line
Collection literals didn't make it into Java 8, but it is possible to use the Stream API to initialize a list in one rather long line:List<String> places = Stream.of("Buenos Aires", "Córdoba",...
View ArticleAnswer by user2801794 for Initialization of an ArrayList in one line
Simply use below code as follows.List<String> list = new ArrayList<String>() {{ add("A"); add("B"); add("C");}};
View ArticleAnswer by Paweł Adamski for Initialization of an ArrayList in one line
With Guava you can write:ArrayList<String> places = Lists.newArrayList("Buenos Aires", "Córdoba", "La Plata");In Guava there are also other useful static constructors. You can read about them here.
View ArticleAnswer by Ozzy for Initialization of an ArrayList in one line
Like Tom said:List<String> places = Arrays.asList("Buenos Aires", "Córdoba", "La Plata");But since you complained of wanting an ArrayList, you should first know that ArrayList is a subclass of...
View ArticleAnswer by user439407 for Initialization of an ArrayList in one line
(Should be a comment, but too long, so new reply). As others have mentioned, the Arrays.asList method is fixed size, but that's not the only issue with it. It also doesn't handle inheritance very well....
View ArticleAnswer by Adrian for Initialization of an ArrayList in one line
Actually, it's possible to do it in one line:Arrays.asList(new MyClass[] {new MyClass("arg1"), new MyClass("arg2")})
View ArticleAnswer by abaelter for Initialization of an ArrayList in one line
public static <T> List<T> asList(T... a) { return new ArrayList<T>(a);}This is the implementation of Arrays.asList, so you could go withArrayList<String> arr =...
View ArticleAnswer by Dawg for Initialization of an ArrayList in one line
In Java, you can't doArrayList<String> places = new ArrayList<String>( Arrays.asList("Buenos Aires", "Córdoba", "La Plata"));As was pointed out, you'd need to do a double brace...
View ArticleAnswer by Randyaa for Initialization of an ArrayList in one line
If you need a simple list of size 1:List<String> strings = new ArrayList<String>(Collections.singletonList("A"));If you need a list of several objects:List<String> strings = new...
View ArticleAnswer by Christoffer Hammarström for Initialization of an ArrayList in one line
The simple answerJava 9 or later:List<String> strings = List.of("foo", "bar", "baz");List.of(...) will give you an immutableList, so it cannot be changed.Which is what you want in most cases...
View ArticleAnswer by George for Initialization of an ArrayList in one line
import com.google.common.collect.ImmutableList;....List<String> places = ImmutableList.of("Buenos Aires", "Córdoba", "La Plata");
View ArticleAnswer by Jordão for Initialization of an ArrayList in one line
You could create a factory method:public static ArrayList<String> createArrayList(String ... elements) { ArrayList<String> list = new ArrayList<String>(); for (String element :...
View ArticleAnswer by Tom for Initialization of an ArrayList in one line
It would be simpler if you were to just declare it as a List - does it have to be an ArrayList?List<String> places = Arrays.asList("Buenos Aires", "Córdoba", "La Plata");Or if you have only one...
View ArticleAnswer by coobird for Initialization of an ArrayList in one line
Actually, probably the "best" way to initialize the ArrayList is the method you wrote, as it does not need to create a new List in any way:ArrayList<String> list = new...
View ArticleInitialization of an ArrayList in one line
I wanted to create a list of options for testing purposes. At first, I did this:ArrayList<String> places = new ArrayList<String>();places.add("Buenos...
View ArticleAnswer by Amar kumar Nayak for Initialization of an ArrayList in one line
You can use of() method from java 9 onwardsList<String> places = List.of("Buenos Aires","Córdoba","La Plata");of() methods create immutable list.If you want to modifie you got exception.
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